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=0.09-Y^2
We move all terms to the left:
-(0.09-Y^2)=0
We get rid of parentheses
Y^2-0.09=0
a = 1; b = 0; c = -0.09;
Δ = b2-4ac
Δ = 02-4·1·(-0.09)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.36}}{2*1}=\frac{0-\sqrt{0.36}}{2} =-\frac{\sqrt{}}{2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.36}}{2*1}=\frac{0+\sqrt{0.36}}{2} =\frac{\sqrt{}}{2} $
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